Returns distinct elements from a sequence.
Syntax
source.Distinct()Example
Enter values below to update the example in real time.
var→numbers→new→List→unique→ToList→Console→WriteLine→string→var numbers = new List<int> { 1, 2, 2, 3, 3, 3 };
var unique = numbers.Distinct().ToList();
Console.WriteLine(string.Join(", ", unique)); // 1, 2, 3